The sum of present ages of A and B is 48 years. Today B is 4 years older than C. The respective ratio of the present ages of A and C is 4 : 7. What was B’s age two years ago.
Answer & explanation
Correct answer: option 2
Let present age of B = x
Prsent age of A = 48 - x
Age of C = x - 4
A : C = 4 : 7
\(\frac{48 - x}{x - 4}\) = \(\frac{4}{7}\)
7(48 - x) = 4(x - 4)
336 - 7x = 4x - 16
11x = 352
x = 32
B's age two years ago = 32 - 2 = 30 years