Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Dual Nature of Radiation and Matter

Question:

If k be the kinetic energy and m the mass of a moving particle then the de-Broglie wavelength of the particle is :

Options:

$λ = \frac{h}{\sqrt{mk}}$

$λ = \frac{2h}{\sqrt{mk}}$

$λ = \frac{h}{2\sqrt{mk}}$

$λ = \frac{h}{\sqrt{2mk}}$

Correct Answer:

$λ = \frac{h}{\sqrt{2mk}}$

Explanation:

$\lambda = \frac{h}{p} = \frac{h}{\sqrt {2mk}}$