If 200 MeV energy is released in the fission of a single nucleus of uranium-235, how many fissions per second will produce a power of 32 kW?

$10^{15}$

The correct answer is Option (2) → $10^{15}$

Energy released per fission: $E = 200\ \text{MeV} = 200 \times 1.6 \times 10^{-13}\ \text{J} = 3.2 \times 10^{-11}\ \text{J}$

Power: $P = 32\ \text{kW} = 32 \times 10^3\ \text{J/s}$

Number of fissions per second: $n = \frac{P}{E} = \frac{32 \times 10^3}{3.2 \times 10^{-11}} = 1 \times 10^{15}\ \text{fissions/s}$

Final Answer: $n = 1 \times 10^{15}\ \text{fissions/s}$