Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Differential Equations

Question:

Th general solution of the differential equation \(\frac{dy}{dx}+\sqrt{\frac{1-y^2}{1-x^2}}=0\) is

Options:

\(\sin^{-1}x-\sin^{-1}y=c\)

\(\sin^{-1}x+\sin^{-1}y=c\)

\(\sin^{-1}x\sin^{-1}y=c\)

\(\sin^{-1}x\sin^{-1}y=x+c\)

Correct Answer:

\(\sin^{-1}x+\sin^{-1}y=c\)

Explanation:

Given differential equation is separable