If $(2x + \frac{1}{2x}) = 5$, then what is the value of $(8x^3 + \frac{1}{8x^3})$ ?
Answer & explanation
Correct answer: option 1
If x + \(\frac{1}{x}\) = n
then, $x^3 +\frac{1}{x^3}$ = n3 - 3 × n
If $(2x + \frac{1}{2x}) = 5$
then, $(8x^3 + \frac{1}{8x^3})$ = 53 - 3 × 5 = 110