Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

Assume that an electric field $(20x^4\hat i)Vm^{-1}$ exists in the region of space. If $V_0$ is the potential at the origin and $V_A$ is the potential at x = 1 m., then the potential difference $V_A-V_0$ is:

Options:

-20 V

+2 V

-4 V

+4 V

Correct Answer:

-20 V

Explanation:

The correct answer is Option (1) → -20 V

For a uniform electric field, it is related to potential difference by -

$E=-\frac{ΔV}{Δx}$

$ΔV$ = Potential difference across $V_A-V_0$

$Δx$ = Displacement along x-axis.

$∴ΔV=-E.Δx$

$=-(20x^4\hat i).(1\hat i)$

$=-20V$