Find at what time between 7 to 8 o'clock will the hands of a clock be in the same straight line but not together.

7 : 5\(\frac{5}{11}\)

Use this formula for this type of question: (5n - 30)× \(\frac{12}{11}\), where n is the minimum value of time which is given in the question.

Here,

n = 7

Therefore,

The hand will be in straight line but not together after = (5 × 7 - 30) × \(\frac{12}{11}\) = 5 × \(\frac{12}{11}\) = × \(\frac{60}{11}\) = 5\(\frac{5}{11}\) min

The hand will be in straight line but not together at = 7 : 5\(\frac{5}{11}\)