A rectangular park was redesigned and as a result of which its length increased by 50%. If the area of the park, remained unchanged, then by how much percentage had the breadth been reduced?

33.33

We have,

Increase in length of park = 50%

Let length and breadth of the park be x and x

= Length of redesigned park = x × (100 + 50) % = 1.5x

Now,

area of park = area of redesigned park

= x × y = 1.5x × breath

= Breath = \(\frac{y}{1.5}\)= \(\frac{2}{3}\)y

Hence, reduced breadth = y – \(\frac{2}{3}\)y = \(\frac{1}{3}\)y

Reduced breadth in percentage = \(\frac{\frac{y}{3}}{y}\) × 100 = 33.33%