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The value of $\frac{3\left(1-2 \sin ^2 x\right)}{\cos ^2 x-\sin ^2 x}$ is: |
4 3 1 2 |
3 |
$\frac{3\left(1-2 \sin ^2 x\right)}{\cos ^2 x-\sin ^2 x}$ = \(\frac{3 ( 1 - 2sin²x )}{cos²x - sin²x}\) = \(\frac{3 ( 1 - sin²x - sin²x)}{cos²x - sin²x}\) { sin²A + cos²A = 1 } = \(\frac{3 ( cos²x - sin²x)}{cos²x - sin²x}\) = 3 |
