P and Q together can do a work in 12 days. P alone can do the same work in 36 days. In how many days can Q alone complete two third part of same work?
Answer & explanation
Correct answer: option 1
P + Q = 12 days,
P = 36 days,
⇒ Simplifying, we can get that Q = 2 (Efficiency)
⇒ \(\frac{2}{3}\) of total work = \(\frac{2}{3}\) x 36 = 24 units.
⇒ Time required for Q alone to complete 24 units = \(\frac{24}{2}\) = 12 days. ..(\(\frac{Work}{Efficiency}\) = Time)