If A (2,3), B(2,4) C(4,9) and D(x,8) are the vertices of a parallelogram ABCD, then find the value of x.
Answer & explanation
Correct answer: option 4
A(2,3), B(2,4) C(4,9) and D(x,8) are the vertices of a parallelogram ABCD.
length of parallel sides are equal
Thus, sqrt[(2-2)^2 + (4-3)^2] = sqrt[(x-4)^2 + (8-9)^2]
sqrt[1] = sqrt[(x-4)^2 + 1]
1 = (x-4)^2 + 1
(x-4)^2 = 0
The correct answer is Option (4) → 4