Practicing Success
If PQ is a tangent of a circle (touches the circle at Q) with centre O and angle POQ is 75o, then what is the value of angle OPQ? |
15o 35o 30o 25o |
15o |
The tangent at any point makes an angle of 90 degrees with the radius. Therefore, \(\angle\)OQP = 90 (Since OQ is the radius and PQ is the tangent at Q.) We need to find the value of \(\angle\)OPQ. However, we know that the sum of the angles in a triangle equals 180 degrees. So, we have \(\angle\)OPQ + \(\angle\)OQP + \(\angle\)POQ = 180 Substituting the given values into the equation, we get \(\angle\)OPQ + 90 + 75 = 180 \(\angle\)OPQ = 180 - 90 - 75 = \(\angle\)OPQ = \({15}^\circ\) Therefore, \(\angle\)OPQ is \({15}^\circ\). |