A circle is inscribed in a triangle ABC. It touches side AB, BC and AC at points R, P and Q, respectively. If AQ = 2.6 cm, PC = 2.7 cm and BR = 3 cm, then the perimeter (in cm)of the triangle △ABC is:

16.6

AQ and AR are two tangents on the circle from point A

= AQ = AR = 2.6 cm

BP and BR are two tangents on the circle from point B

= BR = BP = 3 cm

CP and CQ are two tangents on the circle from point C

= CP = CQ = 2.7 cm

The perimeter of the triangle is AB + BC + CA

= AR + RB + BP + PC + CQ + QA

= 2.6 + 3 + 3 + 2.7 + 2.7 + 2.6

= 16.6

Therefore, the perimeter of the triangle is 16.6 cm.