If $\frac{(15)^3+(4)^3}{(15^2+4^2-k)}=19,$ then what is the value of K ?
Answer & explanation
Correct answer: option 3
$\frac{(15)^3+(4)^3}{(15^2+4^2-k)}=19,$
= $\frac{3775 + 64}{225 + 16 - k)}=19,$
= $\frac{3439}{241 - k)}=19,$
= $3439 = 19 \times (241 - k)$
= 3439 - 4579 = -19k
k = 60