If $\frac{(15)^3+(4)^3}{(15^2+4^2-k)}=19

CUET Preparation Today

Start Free Mocks

Home Questions NZUHKW276V

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If $\frac{(15)^3+(4)^3}{(15^2+4^2-k)}=19,$ then what is the value of K ?

Options:

-60

120

-120

Correct Answer:

Explanation:

$\frac{(15)^3+(4)^3}{(15^2+4^2-k)}=19,$

= $\frac{3775 + 64}{225 + 16 - k)}=19,$

= $\frac{3439}{241 - k)}=19,$

= $3439 = 19 \times (241 - k)$

= 3439 - 4579 = -19k

k = 60