If R(x) denotes the revenue where $R(x)= 4000x-10x^2$ then maximum value of $R(x)$ occurs when x equals :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 200
$R(x)= 4000x-10x^2$
for critical points, $f'(c)=0$
$⇒4000-20c=0$
$⇒20c=4000$
$⇒c=200$
∴ Revenue function is maximum at $x = 200$.