An ammeter of resistance 0.54 Ω reads current unto 1 A. The value of the shunt required to increase the range to 10 A is

0.06 Ω

The correct answer is Option (3) → 0.06 Ω

Given:

Resistance of galvanometer (ammeter) $R_g = 0.54 \, \Omega$

Full scale deflection current $I_g = 1 \, A$

Total current range required $I = 10 \, A$

Shunt current $I_s = I - I_g = 10 - 1 = 9 \, A$

Shunt resistance formula:

$R_s = \frac{I_g \, R_g}{I_s}$

$R_s = \frac{1 \times 0.54}{9}$

$R_s = 0.06 \, \Omega$

Answer: $0.06 \, \Omega$