The ratio of radii of two nuclei having atomic mass numbers 27 and 8 respectively, will be: |
$\frac{R_1}{R_2}=\frac{3}{2}$ $\frac{R_1}{R_2}=\frac{4}{2}$ $\frac{R_1}{R_2}=\frac{6}{4}$ $\frac{R_1}{R_2}=\frac{\sqrt{3}}{2}$ |
$\frac{R_1}{R_2}=\frac{3}{2}$ |
The correct answer is Option (1) → $\frac{R_1}{R_2}=\frac{3}{2}$ The radius of a nucleus is, $R=R_0A^{1/3}$ $R_0$ = Constant A = Mass Number $⇒\frac{R_1}{R_2}=\frac{R_0{A_1}^{1/3}}{R_0{A_2}^{1/3}}=\left(\frac{27}{8}\right)^{1/3}$ $=\frac{3}{2}$ |