Target Exam

CUET

Subject

Physics

Chapter

Atoms

Question:

The ratio of radii of two nuclei having atomic mass numbers 27 and 8 respectively, will be:

Options:

$\frac{R_1}{R_2}=\frac{3}{2}$

$\frac{R_1}{R_2}=\frac{4}{2}$

$\frac{R_1}{R_2}=\frac{6}{4}$

$\frac{R_1}{R_2}=\frac{\sqrt{3}}{2}$

Correct Answer:

$\frac{R_1}{R_2}=\frac{3}{2}$

Explanation:

The correct answer is Option (1) → $\frac{R_1}{R_2}=\frac{3}{2}$

The radius of a nucleus is,

$R=R_0A^{1/3}$

$R_0$ = Constant

A = Mass Number

$⇒\frac{R_1}{R_2}=\frac{R_0{A_1}^{1/3}}{R_0{A_2}^{1/3}}=\left(\frac{27}{8}\right)^{1/3}$

$=\frac{3}{2}$