An unchanged capacitor is connected to a battery. How much amount of energy supplied by the battery is lost as heat while charging the capacitor?
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $\frac{1}{2}QV$
$E_{Battery}=QV$
where,
$Q=CV$ [Charge on capacitor]
V = Voltage of the battery
C = Capacitance of capacitor
$∴E_{Battery}=CV^2$
Energy stored in the capacitor when its fully charged
$E_{capacitor}=\frac{1}{2}CV^2$ [formula]
$∴E_{heat}=CV^2-\frac{1}{2}CV^2=\frac{1}{2}CV^2=\frac{1}{2}QV$