Practicing Success
CUET Preparation Today
CUET
Physics
Semiconductors and Electronic Devices
a
b
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d
$\alpha = \frac{\beta}{1+\beta} = 0.995$
$ \beta = 0.995 + 0.995 \beta , \Rightarrow 0.005 \beta = 0.995$
$ \beta = \frac{0.995}{0.005} = 199$