The length of each equal side of an isosceles triangle is 15 cm and the included angle between those two sides is 90°.Find the area of the triangle.

225 cm2 $\frac{255}{2}$ cm2 $\frac{125}{2}$ cm2 $\frac{225}{2}$ cm2

$\frac{225}{2}$ cm2

We have, Length of each side equal side of an isosceles triangle = 15 cm If the triangle is an isosceles right-angled triangle, then Area of the triangle = \(\frac{1}{2}\) × 15 × 15 = \(\frac{225}{2}\)