Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Wave Optics

Question:

Intensity of central bright fringe due to interference of two identical coherent monochromatic sources is I. If one of the source is switched off, then intensity of central bright fringe becomes

Options:

$\frac{I}{2}$

$\frac{I}{3}$

$\frac{I}{4}$

$I$

Correct Answer:

$\frac{I}{4}$

Explanation:

$I = (a+a)^2 = 4a^2, I'=(a)^2 = a^2$

$∴\frac{I'}{I}=\frac{a^2}{4a^2}=\frac{1}{4},\,I'=\frac{I}{4}$