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The area of a right-angled triangle with base 3 m and hypotenuse 5 m is: |
$4m^2$ $12m^2$ $6m^2$ $15m^2$ |
$6m^2$ |
We have, Base 3 m and hypotenuse 5 m We know that, $hypotenuse^2=Base^2+Perpendicular^2$ $5^2=3^2+Perpendicular^2$ P = 4 So the area = \(\frac{1}{2}\) × B × P = \(\frac{1}{2}\) × 3 × 4 = $6m^2$ |
