The area of a right-angled triangle with base 3 m and hypotenuse 5 m is:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → \(6\,\mathrm{m^2}\)
The area needs the base and the height (the other side of the right angle), which is found from the Pythagoras theorem.
Height \(=\sqrt{5^2-3^2}=\sqrt{25-9}=\sqrt{16}=4\,\mathrm{m}\)
Area \(=\frac{1}{2}\times\text{base}\times\text{height}=\frac{1}{2}\times3\times4=6\,\mathrm{m^2}\)