Let $ƒ: R → R$ be a function defined as $f(x) = x^4$. Which one of the following is true? |
$f$ is one-one and onto $f$ is one-one but not onto. $f$ is onto but not one-one. $f$ is neither one-one nor onto. |
$f$ is neither one-one nor onto. |
The correct answer is Option (4) → $f$ is neither one-one nor onto. Given function $f:R\rightarrow R$ defined by $f(x)=x^4$. Check one–one: $f(1)=1^4=1$ and $f(-1)=(-1)^4=1$ $f(1)=f(-1)$ but $1\neq -1$ So $f$ is not one–one. Check onto: For $y=-1\in R$, there is no real $x$ such that $x^4=-1$. So $f$ is not onto. $f$ is neither one–one nor onto. |