Practicing Success
Practicing Success
CUET Preparation Today
| Let the vectors \(\vec{a}\) and \(\vec{b}\) be such that \(|\vec{a}|=3\) and \(|\vec{b}|=\frac{\sqrt{2}}{3}\) then \(\vec{a}\times \vec{b}\) is a unit vector if the angle between \(\vec{a}\) and \(\vec{b}\) is |
\(\frac{\pi}{6}\) \(\frac{\pi}{4}\) \(\frac{\pi}{3}\) \(\frac{\pi}{2}\) |
| \(\frac{\pi}{4}\) |
| \(\begin{aligned}\text{Given }|\vec{a}\times \vec{b}|&=1\text{ then }\\ |\vec{a}||\vec{b}|\sin \theta &=1\\ 3\cdot \frac{\sqrt{2}}{3}\sin \theta&=1\\ \sin \theta &=\frac{1}{\sqrt{2}}\\ \theta&=\frac{\pi}{4}\end{aligned}\) |
