If $(x - \frac{1}{x} = 4)$, then what is the value of$(x^6 +\frac{1}{x^6})$ ?

4689 4786 5832 5778

5778

If $K-\frac{1}{K}=n$ then, $K^2+\frac{1}{K^2}$ = n2 + 2 If x + \(\frac{1}{x}\)  = n then, $x^3 +\frac{1}{x^3}$ = n3 - 3 × n If $(x - \frac{1}{x} = 4)$ $x^2+\frac{1}{x^2}$ = 42 + 2 = 18 Cubing on both the sides,  $x^6 +\frac{1}{x^6}$ = 183 - 3 × 18 = 5832 - 54 Then the value of$(x^6 +\frac{1}{x^6})$ = 5778