Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Continuity and Differentiability

Question:

Evaluate $\underset{x→2}{\lim}\frac{x^6-24x-16}{x^3+2x-12}$.

Options:

12

0

9

8

Correct Answer:

12

Explanation:

$\underset{x→2}{\lim}\frac{x^6-24x-16}{x^3+2x-12}=\underset{x→2}{\lim}\frac{(x-2)(x^5+2x^4+4x^3+8x^2+16x+8)}{(x-2)(x^2+2x+6)}=\frac{168}{14}=12$