Target Exam

CUET

Subject

Physics

Chapter

Electromagnetic Waves

Question:

For a medium with permittivity (ε) and permeability (μ), the speed of light (v) is given by:

Options:

$v=\sqrt{\frac{μ}{ε}}$

$v=\sqrt{με}$

$v=\sqrt{\frac{1}{με}}$

$v=\sqrt{\frac{ε}{μ}}$

Correct Answer:

$v=\sqrt{\frac{1}{με}}$

Explanation:

The correct answer is Option (3) → $v=\sqrt{\frac{1}{με}}$

The speed of a light in a given medium with permitivity (ε) and permeability (μ) is -

$v=\frac{1}{\sqrt{εμ}}$

$∴c=\frac{1}{\sqrt{ε_0μ_0}}≃3×10^8m/s$