If $A = \begin{bmatrix} 2 & 1 & 0\\ 3 & 1 & 2 \\ 0 & 4 & -1\end{bmatrix}$ then |adj (A)| is equal to
Answer & explanation
Correct answer: option 3
$A = \begin{bmatrix} 2 & 1 & 0\\ 3 & 1 & 2 \\ 0 & 4 & -1\end{bmatrix}$
so A adj A = AI
so |A adj A| = |A|3
so |adj A| = |A|2
so finding |A| first
so $|A| = \begin{vmatrix} 1 & 2\\ 4 & -1 \end{vmatrix} -1\begin{vmatrix} 3 & 2\\ 0 & -1 \end{vmatrix} + 0$
= 2(-1 - 8) - 1(-3)
= 2(-9) + 3
= -18 + 3
= -15 = |A|
so |Adj A| = |A|2 = (-15)2
= 225