If the net flux through a cube is \( 1.05\,\mathrm{N\,m^2\,C^{-1}} \), what will be the total charge inside the cube? (Given : The permittivity of free space is \( 8.85 \times 10^{-12}\,\mathrm{C^2\,N^{-1}\,m^{-2}} \)).
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → \( 9.29 \times 10^{-12}\,\mathrm{C} \)
Gauss's law says that the net electric flux through a closed surface equals the enclosed charge divided by \( \varepsilon_0 \).
\( \displaystyle \Phi = \frac{q}{\varepsilon_0} \;\Rightarrow\; q = \varepsilon_0\,\Phi \)
\( \displaystyle q = 8.85\times10^{-12} \times 1.05 = 9.29\times10^{-12}\,\mathrm{C} \)