The sum of the ages of father and his son is 44 years. If 6 years later the father will be 3 times as old as his son, what are their present ages?

36,8

According to the question:

F + S = 44 -----1st equation

F = 44 - S

After 6 years:

F + 6 = 3(S + 6) -----2nd equation

F + 6 = 3S + 18

44 - S + 6 = 3S + 18

4S = 32 years

S = 8 years

F = 44 - 8 = 36 years

So, the respective age of father and son is 36 and 8 years.