The sum of the ages of father and his son is 44 years. If 6 years later the father will be 3 times as old as his son, what are their present ages?
Answer & explanation
Correct answer: option 2
According to the question:
F + S = 44 -----1st equation
F = 44 - S
After 6 years:
F + 6 = 3(S + 6) -----2nd equation
F + 6 = 3S + 18
44 - S + 6 = 3S + 18
4S = 32 years
S = 8 years
F = 44 - 8 = 36 years
So, the respective age of father and son is 36 and 8 years.