Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Probability Distributions

Question:

The probability distribution of a random variable X is given by :

X 1 2 3 4 5
P(X) 2K K 3K 4K K

Then the value of K is :

Options:

$\frac{1}{12}$

$\frac{1}{11}$

$\frac{1}{10}$

$\frac{1}{9}$

Correct Answer:

$\frac{1}{11}$

Explanation:

The correct answer is Option (2) → $\frac{1}{11}$

The value of probability should be equal to 1.

$⇒2k+k+3k+4k+k=1$

$⇒11k=1$

$⇒k=\frac{1}{11}$