Given a matrix \( A=\begin{bmatrix}0 & 3 & -8\\-3 & 0 & 13\\8 & -13 & 0\end{bmatrix} \).Which of the following statements is/are TRUE ?
(A) The matrix A is a skew-symmetric matrix.
(B) The matrix A is a symmetric matrix.
(C) The matrix A is a singular matrix.
(D) The matrix A is a non-singular matrix.
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → (A) and (C) only
Taking the transpose of A:
\( \displaystyle A^T=\begin{bmatrix}0 & -3 & 8\\3 & 0 & -13\\-8 & 13 & 0\end{bmatrix} \)
\( \displaystyle =-A \)
So A is skew-symmetric. Expanding the determinant along the first row:
\( \displaystyle |A|=0(0+169)-3(0-104)+(-8)(39-0) \)
\( \displaystyle =312-312 \)
\( \displaystyle =0 \)
So \( A^T=-A \) and \( |A|=0 \).
Checking the statements
(A) The matrix A is a skew-symmetric matrix. — Correct. \( A^T=-A \).
(B) The matrix A is a symmetric matrix. — Incorrect. \( A^T=-A\ne A \), since A is not the zero matrix.
(C) The matrix A is a singular matrix. — Correct. \( |A|=0 \).
(D) The matrix A is a non-singular matrix. — Incorrect. \( |A|=0 \), so A is singular.
Tip: Every skew-symmetric matrix of odd order has determinant 0, so it is always singular; no calculation is needed.