The demand function for a monopolist is given by \( x=100-4p \), then the marginal revenue, when \( x=6 \) is (where \( x \) is the number of units and \( p \) is the price per unit)
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 22
From the demand function, the price is
\( \displaystyle p=\frac{100-x}{4} \)
So the revenue is
\( \displaystyle R=px=\frac{100x-x^2}{4} \)
The marginal revenue is
\( \displaystyle \text{MR}=\frac{dR}{dx}=\frac{100-2x}{4} \)
At x = 6:
\( \displaystyle \text{MR}=\frac{100-12}{4}=22 \)