CUET Preparation Today
$\frac{5-2x}{3}≤\frac{x}{6}-5$ |
$[8, ∞)$ $[7, ∞)$ $[9, ∞)$ $[5, ∞)$ |
$[8, ∞)$ |
The correct answer is option (1) : $[8, ∞)$ $\frac{5-2x}{3}≤\frac{x}{6}-5$ Multiply both sides by 6 $2(5-2x)≤x-30$ $-5x≤-40$ $x≥8$ ∴Solution is $[8, ∞)$ |
