CUET Preparation Today
An urn contains 25 balls numbered from 1 to 25. Suppose an odd number is considered a “success”. Two balls are drawn from the urn with replacement probability of getting two successes: |
${^2C}_2(\frac{13}{25})^2$ ${^2C}_1(\frac{13}{25}×\frac{12}{25})$ $1-{^2C}_0(\frac{12}{25})^2$ ${^2C}_0(\frac{12}{25})^2$ |
${^2C}_2(\frac{13}{25})^2$ |
P(odd no.) = success(p) = $\frac{12}{25}$; P(even number) = failure(q) = $\frac{12}{25}$ |
