Mohan is a father of \(3\) children with at least one boy. The probability that he has \(2\) boys and \(1\) girl is

\(\frac{1}{2}\) \(\frac{1}{3}\) \(\frac{1}{4}\) \(\frac{2}{3}\)

\(\frac{1}{3}\)

Total ways of arranging given \(3\) children are \(3\).