A is thrice as old as B . 7 years ago A was four times as old as B . Find the present age of A.
Answer & explanation
Correct answer: option 1
Let age of A 7 years ago = 4x and age of B 7 years ago = x
Now , according to question
\(\frac{4x+ 7}{x+7}\) = \(\frac{3}{1}\)
4x + 7 = 3x + 21
x = 14
so,
A's Present age = 4 x 14 + 7 = 63