A is thrice as old as B . 7 years ago A was four times as old as B . Find the present age of A.

63 56 49 66

63

Let age of  A 7 years ago = 4x and age of B 7 years ago = x  Now , according to question  \(\frac{4x+ 7}{x+7}\) = \(\frac{3}{1}\) 4x  + 7 = 3x + 21 x = 14 so,        A's Present age = 4 x 14 + 7 = 63