In a equilateral triangle ABC, if AD ⊥ BC, then :
Answer & explanation
Correct answer: option 3
AB2 = BD2 + AD2
AB2 = (\(\frac{1}{2AB}\))2 + AD2
∴ 4 AB2 = AB2 + 4 AD2
⇒ 3 AB2 = 4 AD2
In a equilateral triangle ABC, if AD ⊥ BC, then :
Correct answer: option 3
AB2 = BD2 + AD2
AB2 = (\(\frac{1}{2AB}\))2 + AD2
∴ 4 AB2 = AB2 + 4 AD2
⇒ 3 AB2 = 4 AD2