The distance between two stations A and B is 575 km. A train starts from station ‘A’ at 3:00 p.m. and moves towards station ‘B’ at an average speed of 50 km/h. Another train starts from station ‘B’ at 3:30 p.m. and moves towards station ‘A’ at an average speed of 60 km/h. How far from station ‘A’ will the trains meet ?

275 km

The distance between A and B = 575 km,

Speed of 1st train = 50 km/hr

Speed of 2nd train = 60 km/hr

Distance = Speed × Time

Distance covered by first train in 30 min (1/2 hr) = 50 × \(\frac{1}{2}\) = 25 km

Remaining distance = 575 - 25 = 550 km

Relative speed ( when both moves in opposite direction) = 50 + 60 = 110 km/hr

As we know,

Time = \(\frac{Distance}{Speed}\)

Trains meet each other in = \(\frac{550}{110}\) = 5 hrs

Distance covered in 5 hrs by 1st train = 5 × 50 = 250 km

Total distance covered by first train = 25 + 250 = 275 km

Both trains meet each other 275 km far from station A.