A sum of money becomes \(\frac{768}{243}\) times of itself in 4 years. Find the rate of interest if compounded annually.

33.33 %

A = P (1+ \(\frac{R}{100}\))⁴                            

\(\frac{768}{243}\) = (1+ \(\frac{R}{100}\))⁴      

\(\frac{256}{81}\) = (1+ \(\frac{R}{100}\))⁴

(\(\frac{4}{3}\))⁴ =   (1+ \(\frac{R}{100}\))⁴

\(\frac{1}{3}\) = \(\frac{R}{100}\)

R = \(\frac{100}{3}\) = 33.33 %