Answer & explanation
Correct answer: option 3
$ \text{Radius of the disc is } R = \frac{h}{\sqrt{\mu^2 -1}} = \frac{4}{\sqrt{(\frac{5}{3})^2 -1}} = 3m$
$\text{Diameter of the disc is } 6m.$
Correct answer: option 3
$ \text{Radius of the disc is } R = \frac{h}{\sqrt{\mu^2 -1}} = \frac{4}{\sqrt{(\frac{5}{3})^2 -1}} = 3m$
$\text{Diameter of the disc is } 6m.$