Two trains A and B start their journey from X and Y respectively towards each other. When they will cross each other then, train A and B will takes 36 hrs and 25 hrs respectively to reach their destination. The speed of train A is 25 km/hr. Find the distance between X and Y?

1650

\(\frac{S_{A} }{S_{B}}\) = \(\sqrt{\frac{t_{B}}{t_{A}}}\) \(\Rightarrow \) \(\sqrt{\frac{25}{36}}\) \(\Rightarrow \)\(\frac{5}{6}\)

Speed of A \(\Rightarrow \) 5 \(\longrightarrow \) 25 km/h (given)

Speed of B \(\Rightarrow \) 6 \(\longrightarrow \) 30 km/h

now distance \(\Rightarrow \) 25 km/h × 36 hrs + 30 km/h × 25

\(\Rightarrow \) 900 +750

\(\Rightarrow \) 1650 km