A circle touches the side BC of a $\triangle$ABC at P and also touches AB and AC produced at Q and R, respectively. If the perimeter of $\triangle$ABC = 26.4 cm, then the length of AQ is:
Answer & explanation
Correct answer: option 1
AQ = AR [Tangents]
BP = BQ [Tangents]
CP = CR [Tangents]
Perimeter of \(\Delta \)ABC = AB + BP + PC + AC
26.4 = AB + BQ + CR + AC
26.4 = AQ + AR
26.4 = AQ + AQ
26.4 = 2AQ
AQ = \(\frac{26.4}{2}\)
AQ = 13.2 cm.