A circle touches the side BC of a $\triangle$ABC at P and also touches AB and AC produced at Q and R, respectively. If the perimeter of $\triangle$ABC = 26.4 cm, then the length of AQ is:

13.2 cm

AQ = AR [Tangents]

BP = BQ [Tangents]

CP = CR [Tangents]

Perimeter of \(\Delta \)ABC = AB + BP + PC + AC

26.4 = AB + BQ + CR + AC

26.4 = AQ + AR

26.4 = AQ + AQ

26.4 = 2AQ

AQ =  \(\frac{26.4}{2}\)

AQ = 13.2 cm.