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-- Mathematics - Section B2
Calculus
If $x=6t^4, y =4t^3$, then the value of $\frac{d^2y}{dx^2}$ at $t=1$ is :
$-\frac{1}{24}$
$\frac{1}{2}$
$\frac{1}{12}$
$-\frac{1}{48}$