Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B2

Chapter

Calculus

Question:

If $x=6t^4, y =4t^3$, then the value of $\frac{d^2y}{dx^2}$ at $t=1$ is :

Options:

$-\frac{1}{24}$

$\frac{1}{2}$

$\frac{1}{12}$

$-\frac{1}{48}$

Correct Answer:

$-\frac{1}{48}$