Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Semiconductors and Electronic Devices

Question:

Options:

a

b

c

d

Correct Answer:

c

Explanation:

$\lambda = \frac{hc}{\Delta E} = \frac{12400}{2.5} = 5000A^0$

$\text{Any wavelength below this can do the job so correct option is }4000A^0.$