Practicing Success
If the mean and the variance of a binomial distribution are 6 and 3 respectively, then the probability of five successes is : |
${^{12}C}_5 \left(\frac{1}{2}\right)^{12}$ ${^{16}C}_5 \left(\frac{1}{4}\right)^{5}\left(\frac{3}{4}\right)^{11}$ ${^{12}C}_5 \left(\frac{1}{2}\right)^{5} \left(\frac{2}{3}\right)^{7}$ ${^{12}C}_5 \left(\frac{1}{6}\right)^{5} \left(\frac{5}{6}\right)^{7}$ |
${^{12}C}_5 \left(\frac{1}{2}\right)^{12}$ |