The value of $\frac{(2.7)^3-(2.2)^3}{(2.7)^2+2.7×2.2+(2.2)^2}$ is
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 0.5
The expression is in the form:
$\frac{a^3 - b^3}{a^2 + ab + b^2}$
where:
- $a = 2.7$
- $b = 2.2$
We know the identity for the difference of cubes is:
$a^3 - b^3 = (a - b)(a^2 + ab + b^2)$
By rearranging this formula, we get:
$\frac{a^3 - b^3}{a^2 + ab + b^2} = a - b$
Substituting the values of $a$ and $b$ back into the simplified expression:
$\text{Value} = 2.7 - 2.2$
$\text{Value} = 0.5$