In an a.c. circuit, a resistor, a capacitor and an inductor are connected in series, in which \( X_C = X_L = R \). The impedance of this circuit will be
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → \( R \)
In a series LCR circuit the inductive and capacitive reactances act in opposite directions in the phasor diagram, so only their difference adds to the resistance.
\( \displaystyle Z = \sqrt{R^{2} + (X_L - X_C)^{2}} \)
Putting \( X_L = X_C \):
\( \displaystyle Z = \sqrt{R^{2} + 0} = R \)
This is the resonance condition: the reactances cancel and the impedance is just the resistance.
Note: This question is from NCERT (2026-27). NTA sets numerical questions from NCERT too, so do not ignore NCERT while practising numericals.
NCERT (2026-27):
Resonance – “… For an RLC circuit driven with voltage of amplitude vm and frequency ω, we found that the current amplitude is given by
\( \displaystyle i_m = \frac{v_m}{Z} = \frac{v_m}{\sqrt{R^2 + (X_C - X_L)^2}} \)
with Xc = 1/ωC and XL = ωL. So if ω is varied, then at a particular frequency ω0, Xc = XL, and the impedance is minimum
\( \displaystyle Z = \sqrt{R^2 + 0^2} = R \)”