A circular coil of 20 turns and radius 10 cm is placed in a uniform magnetic field of 0.10 T normal to the plane of the coil. If the current in the coil is 5 A. The total torque on the coil is:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → Zero
The torque on the circular coil is -
$τ=nIAB\sin θ$
$τ=nIAB\sin(0°)=0$