A circular coil of 20 turns and radius 10 cm is placed in a uniform magnetic field of 0.10 T normal to the plane of the coil. If the current in the coil is 5 A. The total torque on the coil is: |
$3.14 \times 10^{-3} N m$ $3.14 \times 10^{-2} N m$ 3.14 N m Zero |
Zero |
The correct answer is Option (4) → Zero |