The probability that a card drawn from a pack of 52 cards will be a red card or an ace (including the chance of any red ace), is:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 7/13
For “A or B”, \(P(A\text{ or }B)=P(A)+P(B)-P(A\text{ and }B)\): the cards that are both red and an ace would otherwise be counted twice.
Cards that are red or an ace: \(26+4-2=28\)
Probability, 28 favourable cards out of 52: \(\displaystyle \frac{28}{52}=\frac{7}{13}\)
Adding 26 and 4 without taking away the two red aces gives \(\frac{30}{52}=\frac{15}{26}\), the figure in Option (4).